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Fixed results for NULL and NaN distances - fixes #205
Co-authored-by: Xiaoran Wang <wxiaoran@vmware.com>
This commit is contained in:
@@ -11,9 +11,16 @@ SELECT * FROM t ORDER BY val <=> '[3,3,3]';
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[1,2,4]
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(3 rows)
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SELECT * FROM t ORDER BY val <=> (SELECT NULL::vector);
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val
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-----
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(0 rows)
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <=> '[0,0,0]') t2;
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count
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-------
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3
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(1 row)
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <=> (SELECT NULL::vector)) t2;
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count
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-------
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3
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(1 row)
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DROP TABLE t;
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@@ -12,9 +12,10 @@ SELECT * FROM t ORDER BY val <#> '[3,3,3]';
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[0,0,0]
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(4 rows)
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SELECT * FROM t ORDER BY val <#> (SELECT NULL::vector);
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val
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-----
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(0 rows)
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <#> (SELECT NULL::vector)) t2;
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count
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-------
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4
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(1 row)
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DROP TABLE t;
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@@ -13,9 +13,13 @@ SELECT * FROM t ORDER BY val <-> '[3,3,3]';
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(4 rows)
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SELECT * FROM t ORDER BY val <-> (SELECT NULL::vector);
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val
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-----
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(0 rows)
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val
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---------
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[0,0,0]
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[1,1,1]
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[1,2,3]
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[1,2,4]
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(4 rows)
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SELECT COUNT(*) FROM t;
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count
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@@ -7,6 +7,7 @@ CREATE INDEX ON t USING ivfflat (val vector_cosine_ops) WITH (lists = 1);
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INSERT INTO t (val) VALUES ('[1,2,4]');
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SELECT * FROM t ORDER BY val <=> '[3,3,3]';
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SELECT * FROM t ORDER BY val <=> (SELECT NULL::vector);
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <=> '[0,0,0]') t2;
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <=> (SELECT NULL::vector)) t2;
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DROP TABLE t;
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@@ -7,6 +7,6 @@ CREATE INDEX ON t USING ivfflat (val vector_ip_ops) WITH (lists = 1);
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INSERT INTO t (val) VALUES ('[1,2,4]');
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SELECT * FROM t ORDER BY val <#> '[3,3,3]';
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SELECT * FROM t ORDER BY val <#> (SELECT NULL::vector);
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SELECT COUNT(*) FROM (SELECT * FROM t ORDER BY val <#> (SELECT NULL::vector)) t2;
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DROP TABLE t;
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